Solve the quadratic equation: 2x2−7x+3=02x^2 - 7x + 3 = 0

Answer: The solutions are x=3x = 3 and x=12x = \frac{1}{2}.

Step-by-step solution

Step 1: Identify coefficients

We first identify the coefficients aa, bb, and cc from the given quadratic equation 2x2−7x+3=02x^2 - 7x + 3 = 0. These coefficients are essential for applying the quadratic formula.

Step 2: Apply the quadratic formula

The quadratic formula is used to find the roots of any quadratic equation in the form ax2+bx+c=0ax^2 + bx + c = 0. This formula provides a direct method to solve for xx.

Step 3: Substitute values into the formula

Now we substitute the values of a=2a=2, b=−7b=-7, and c=3c=3 into the quadratic formula. Careful substitution helps prevent errors in calculation.

Step 4: Simplify the expression under the square root

We calculate the terms inside the square root. (−7)2(-7)^2 becomes 4949, and 4(2)(3)4(2)(3) becomes 2424. The denominator 2(2)2(2) becomes 44.

Step 5: Calculate the square root

Subtracting 2424 from 4949 gives 2525. The square root of 2525 is 55. We now have a simplified expression ready for finding the two possible values of xx.

Step 6: Calculate the two possible values for x

The ±\pm sign indicates two solutions. We calculate one root using the positive sign and the other root using the negative sign.

Step 7: Final calculation of roots

Performing the final division, we find the two roots of the quadratic equation. The first root is 33 and the second root is 1/21/2.

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