Solve the quadratic equation using factorization: x2−5x+6=0x^2 - 5x + 6 = 0.

Answer: The solutions are x=2x = 2 and x=3x = 3.

Step-by-step solution

Step 1: Identify coefficients and find factors

We need to factor the quadratic equation x2−5x+6=0x^2 - 5x + 6 = 0. This is in the standard form ax2+bx+c=0ax^2 + bx + c = 0, where a=1a=1, b=−5b=-5, and c=6c=6. We need to find two numbers that multiply to cc (which is 6) and add up to bb (which is -5).

Step 2: Find the two numbers

The two numbers that satisfy these conditions are -2 and -3, because their product is (−2)×(−3)=6(-2) \times (-3) = 6 and their sum is (−2)+(−3)=−5(-2) + (-3) = -5.

Step 3: Rewrite the middle term

Now, we rewrite the middle term, −5x-5x, using these two numbers: −2x−3x-2x - 3x. This allows us to group terms for factorization.

Step 4: Factor by grouping

We group the terms and factor out the common factors from each pair. From the first two terms, x2−2xx^2 - 2x, we factor out xx. From the last two terms, −3x+6-3x + 6, we factor out −3-3.

Step 5: Factor out the common binomial

Notice that (x−2)(x - 2) is a common binomial factor in both terms. We factor it out to get the completely factored form of the quadratic equation.

Step 6: Solve for x

For the product of two factors to be zero, at least one of the factors must be zero. So, we set each factor equal to zero and solve for xx.

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