Suppose p is greatest of five consecutive numbers. Describe the other four numbers in terms of p

Answer: The other four numbers in terms of pp are p−1p - 1, p−2p - 2, p−3p - 3, and p−4p - 4.

Step-by-step solution

Step 1: Understand consecutive numbers

Consecutive numbers are numbers that follow each other in order without any gaps. Each successive number increases by 11, which means each preceding number is obtained by subtracting 11 from the number after it.

Step 2: Express preceding numbers in terms of pp

Since pp is the greatest of the 55 consecutive numbers, it is the fifth and last number in the sequence. By repeatedly subtracting 11, we determine the values of the previous four numbers: p−1p - 1, p−2p - 2, p−3p - 3, and p−4p - 4.

Step 3: State the complete set of numbers

Arranged in ascending order, the five consecutive numbers are p−4p - 4, p−3p - 3, p−2p - 2, p−1p - 1, and pp. Therefore, the other four numbers expressed in terms of pp are p−1p - 1, p−2p - 2, p−3p - 3, and p−4p - 4.

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