The angle of elevation of a cloud from a point hh meters above a lake is α\alpha and the angle of depression of its reflection in the lake is β\beta. Prove that the height of the cloud is: h(tan⁡β+tan⁡α)tan⁡β−tan⁡α\frac{h(\tan \beta + \tan \alpha)}{\tan \beta - \tan \alpha}

Answer: The height of the cloud is h(tan⁡β+tan⁡α)tan⁡β−tan⁡α\frac{h(\tan \beta + \tan \alpha)}{\tan \beta - \tan \alpha}

Step-by-step solution

Step 1: Define variables and set up the diagram

We begin by defining the key points and distances involved in the problem. Let CC represent the cloud, C′C' its reflection in the lake, and PP the observation point. The lake surface is denoted by LL. The height of the observation point PP above the lake surface is given as hh. We assume the height of the cloud above the lake surface is HH and the horizontal distance from the observation point to the vertical projection of the cloud on the lake surface is xx.

Step 2: Formulate equations using angles of elevation and depression

From the observation point PP, the angle of elevation to the cloud CC is α\alpha. The vertical distance from PP to CC is H−hH-h. Thus, tan⁡α=H−hx\tan \alpha = \frac{H-h}{x}. The angle of depression to the reflection C′C' is β\beta. The reflection C′C' is at a depth HH below the lake surface, so its distance from the observation point's horizontal line is H+hH+h. Thus, tan⁡β=H+hx\tan \beta = \frac{H+h}{x}.

Step 3: Solve for x from both equations

We can rearrange both equations (1) and (2) to solve for xx. This will allow us to equate the expressions for xx in the next step.

Step 4: Equate the expressions for x and solve for H

By equating the two expressions for xx, we form a single equation involving HH, hh, tan⁡α\tan \alpha, and tan⁡β\tan \beta. We then expand and rearrange the terms to isolate HH on one side, leading to the desired formula for the height of the cloud.

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