The coordinates of the point A, where AB is the diameter of the circle whose centre is (3, 2) and B (7, 4) is :

Answer: The coordinates of point A are (−1,0)(-1, 0).

Step-by-step solution

Step 1: Understand the relationship between center, diameter, and endpoints

The center of a circle is always the midpoint of its diameter. We are given the coordinates of the center and one endpoint of the diameter. We need to find the coordinates of the other endpoint.

Step 2: Recall the midpoint formula

The midpoint formula states that for two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), their midpoint MM is given by the average of their respective coordinates.

Step 3: Substitute known values into the midpoint formula

Let the coordinates of point A be (xA,yA)(x_A, y_A). We substitute the coordinates of the center (3,2)(3, 2) as the midpoint MM, and the coordinates of point B (7,4)(7, 4) as (x2,y2)(x_2, y_2) into the midpoint formula.

Step 4: Solve for the x-coordinate of A

To find the xx -coordinate of A, we equate the xx -coordinate of the center to the xx -component of the midpoint formula and solve for xAx_A.

Step 5: Solve for the y-coordinate of A

Similarly, to find the yy -coordinate of A, we equate the yy -coordinate of the center to the yy -component of the midpoint formula and solve for yAy_A.

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