The line segment joining the points A(3, 2) and B(6, -7) is trisected at the points P and Q such that P is nearer to A. If P also lies on the line 2x−y+k=02x - y + k = 0 find the value of k.

Answer: The value of kk is −9-9.

Step-by-step solution

Step 1: Understand Trisection and Section Formula

When a line segment is trisected, it means it is divided into three equal parts. Since P is nearer to A, point P divides the line segment AB in the ratio 1:2. This means the distance AP is one-third of AB, and PB is two-thirds of AB.

Step 2: Apply Section Formula to find coordinates of P

We use the section formula to find the coordinates of point P. Here, (x1,y1)=(3,2)(x_1, y_1) = (3, 2), (x2,y2)=(6,−7)(x_2, y_2) = (6, -7), and the ratio m:n=1:2m:n = 1:2. Substitute these values into the formula to find the coordinates of P.

Step 3: Calculate coordinates of P

Perform the arithmetic operations to simplify the expressions for the x and y coordinates of P. This gives us the exact coordinates of point P.

Step 4: Substitute P's coordinates into the line equation

The problem states that point P lies on the line 2x−y+k=02x - y + k = 0. This means that the coordinates of P must satisfy the equation of the line. Substitute the x and y coordinates of P into the line equation.

Step 5: Solve for k

Simplify the equation by performing the multiplication and addition. Then, isolate kk to find its value. This will give us the final answer.

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