The line segment joining the points A(3, 2) and B(6, -7) is trisected at the points P and Q such that P is nearer to A. If P also lies on the line 2x - y + k=0 find the value of k.
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Step-by-Step Solution
Step 1: Understand Trisection and Section Formula
When a line segment is trisected, it means it is divided into three equal parts. Since P is nearer to A, point P divides the line segment AB in the ratio 1:2. This means the distance AP is one-third of AB, and PB is two-thirds of AB.
Step 2: Apply Section Formula to find coordinates of P
We use the section formula to find the coordinates of point P. Here, (x1,y1)=(3,2), (x2,y2)=(6,−7), and the ratio m:n=1:2. Substitute these values into the formula to find the coordinates of P.
Step 3: Calculate coordinates of P
Perform the arithmetic operations to simplify the expressions for the x and y coordinates of P. This gives us the exact coordinates of point P.
Step 4: Substitute P's coordinates into the line equation
The problem states that point P lies on the line 2x−y+k=0. This means that the coordinates of P must satisfy the equation of the line. Substitute the x and y coordinates of P into the line equation.
Step 5: Solve for k
Simplify the equation by performing the multiplication and addition. Then, isolate k to find its value. This will give us the final answer.