First, we convert the mixed fractions to improper fractions: 75(1)/(4) = (75 × 4 + 1)/(4) = (301)/(4) and 55(1)/(2) = (55 × 2 + 1)/(2) = (111)/(2).

To add the fractions, convert (111)/(2) to have a denominator of 4, which gives (222)/(4). Adding the numerators gives (301 + 222)/(4) = (523)/(4) L, or 130(3)/(4) L.

We convert the sold quantity 85(3)/(4) to an improper fraction: (85 × 4 + 3)/(4) = (343)/(4). Subtracting this from the total gives (523 - 343)/(4) = (180)/(4) = 45 L.

The milk society good 75 1 by 4 L in the morning and if 55 1 by 2 little in the evening of this 85 3/4 litre of milk is sold how much milk is left in

Answer: 45 L

Step-by-step solution

Step 1: Calculate the total milk collected

First, we convert the mixed fractions to improper fractions: $75\frac{1}{4} = \frac{75 \times 4 + 1}{4} = \frac{301}{4}$ and $55\frac{1}{2} = \frac{55 \times 2 + 1}{2} = \frac{111}{2}$ .

Step 2: Add the quantities of milk collected

To add the fractions, convert $\frac{111}{2}$ to have a denominator of $4$ , which gives $\frac{222}{4}$ . Adding the numerators gives $\frac{301 + 222}{4} = \frac{523}{4}\text{ L}$ , or $130\frac{3}{4}\text{ L}$ .

Step 3: Subtract the sold milk to find the remaining milk

We convert the sold quantity $85\frac{3}{4}$ to an improper fraction: $\frac{85 \times 4 + 3}{4} = \frac{343}{4}$ . Subtracting this from the total gives $\frac{523 - 343}{4} = \frac{180}{4} = 45\text{ L}$ .

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