The number of sequences of ten terms, whose terms are either 00, 11, or 22, that contain exactly five 11 ’s and exactly three 22 ’s is equal to:

Answer: 2520

Step-by-step solution

Step 1: Determine the number of terms for each digit

We are given a sequence of ten terms. The terms can be 00, 11, or 22. We need to find the number of such sequences that contain exactly five 11 's and exactly three 22 's. First, let's identify the total number of terms and the count for each specified digit.

Step 2: Calculate the number of 0's

Since the total number of terms is 1010, and we have five 11 's and three 22 's, the remaining terms must be 00 's. We calculate the number of 00 's by subtracting the count of 11 's and 22 's from the total number of terms.

Step 3: Apply the multinomial coefficient formula

This problem involves arranging a set of items where some items are identical. The formula for permutations with repetitions (also known as the multinomial coefficient) is used here. We have NN total terms, with n1n_1 terms of type 1, n2n_2 terms of type 2, and n3n_3 terms of type 3.

Step 4: Calculate the factorial values

Before performing the division, we need to calculate the factorial of each number involved in the formula. This step breaks down the calculation into manageable parts.

Step 5: Compute the final result

Substitute the calculated factorial values into the multinomial coefficient formula and perform the division to find the total number of unique sequences.

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