The real x for which 2(2x+3)−10<6(x−2)2(2x + 3) - 10 < 6 (x - 2) is :

Answer: x>4x > 4

Step-by-step solution

Step 1: Expand both sides of the inequality

First, we distribute the numbers outside the parentheses to the terms inside on both sides of the inequality. On the left side, 2×2x=4x2 \times 2x = 4x and 2×3=62 \times 3 = 6. On the right side, 6×x=6x6 \times x = 6x and 6×−2=−126 \times -2 = -12.

Step 2: Simplify both sides

Next, we combine the constant terms on the left side of the inequality. 6−106 - 10 simplifies to −4-4. The right side remains 6x−126x - 12.

Step 3: Collect x terms on one side

To isolate the variable xx, we move all terms containing xx to one side and constant terms to the other. Subtract 6x6x from both sides and add 44 to both sides.

Step 4: Simplify and solve for x

Combine the terms: 4x−6x=−2x4x - 6x = -2x and −12+4=−8-12 + 4 = -8. Finally, divide both sides by −2-2. Remember to reverse the inequality sign when dividing by a negative number.

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