The vertices of a triangle are A(5,−1)A(5, -1), B(−3,−2)B(-3, -2), and C(1,8)C(1, 8). Find the length of the median drawn from vertex AA to side BCBC, and determine the coordinates of the centroid of △ABC\triangle ABC.

Answer: The length of the median drawn from vertex A to side BC is 2132\sqrt{13} units, and the coordinates of the centroid of △ABC\triangle ABC are (1,53)(1, \frac{5}{3}).

Step-by-step solution

Step 1: Find the midpoint of BC

To find the median from vertex A to side BC, we first need to find the midpoint of side BC. Let's call this midpoint D. We use the midpoint formula, which averages the x-coordinates and y-coordinates of points B and C.

Step 2: Calculate coordinates of D

Substitute the coordinates of B (−3,−2)(-3, -2) and C (1,8)(1, 8) into the midpoint formula. This gives us the coordinates of point D, which is (−1,3)(-1, 3).

Step 3: Calculate the length of the median AD

Now that we have the coordinates of A (5,−1)(5, -1) and D (−1,3)(-1, 3), we can find the length of the median AD using the distance formula. The distance formula calculates the length of a line segment between two points.

Step 4: Calculate length of AD

Substitute the coordinates of A (5,−1)(5, -1) and D (−1,3)(-1, 3) into the distance formula. After performing the calculations, we find the length of the median AD to be 52\sqrt{52}, which simplifies to 2132\sqrt{13} units.

Step 5: Find the coordinates of the centroid

The centroid of a triangle is the point where the three medians intersect. Its coordinates are found by averaging the x-coordinates and y-coordinates of all three vertices of the triangle.

Step 6: Calculate coordinates of the centroid G

Substitute the coordinates of A (5,−1)(5, -1), B (−3,−2)(-3, -2), and C (1,8)(1, 8) into the centroid formula. After summing the coordinates and dividing by 3, we find the centroid G to be (1,53)(1, \frac{5}{3}).

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