Two dice are thrown at the same time and the product of the numbers appearing on them is noted. The probability that the product of the numbers lies between 8 and 13 is

Answer: The probability that the product of the numbers lies between 8 and 13 is 736\frac{7}{36}.

Step-by-step solution

Step 1: Determine the sample space

When two dice are thrown, each die has 6 possible outcomes (1, 2, 3, 4, 5, 6). The total number of possible outcomes in the sample space is the product of the outcomes for each die.

Step 2: List outcomes with product between 8 and 13

We need to find pairs of numbers whose product is greater than 8 and less than 13. We list all such pairs: (2,4)(2{,}4) product is 8 (not included), (2,5)(2{,}5) product is 10, (2,6)(2{,}6) product is 12, (3,3)(3{,}3) product is 9, (3,4)(3{,}4) product is 12, (4,2)(4{,}2) product is 8 (not included), (4,3)(4{,}3) product is 12, (5,2)(5{,}2) product is 10, (6,2)(6{,}2) product is 12. The products must be strictly between 8 and 13, so 8 and 13 are excluded. The favorable outcomes are those with products 9, 10, 11, 12.

Step 3: Count favorable outcomes

Counting the listed pairs from the previous step, we find there are 7 favorable outcomes.

Step 4: Calculate the probability

The probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.

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