Let the required second number be b. Substituting HCF = 8, LCM = 240, and a = 48 into the equation gives 8 × 240 = 48 × b.

To solve for b, we divide the product of 8 and 240 by 48. Simplifying the fraction, (240)/(48) = 5, and multiplying by 8 gives b = 40.

two positive injust have it's your fate and LCM 240 if one number is 48 find the other number

Answer: 40

Step-by-step solution

Step 1: State the relationship between HCF, LCM, and two numbers

For any two positive integers $a$ and $b$ , the product of their Highest Common Factor and Least Common Multiple equals the product of the two numbers itself. Here, we are given $\text{HCF} = 8$ , $\text{LCM} = 240$ , and one number $a = 48$ .

Step 2: Substitute the given values into the formula

Let the required second number be $b$ . Substituting $\text{HCF} = 8$ , $\text{LCM} = 240$ , and $a = 48$ into the equation gives $8 \times 240 = 48 \times b$ .

Step 3: Solve for the other number

To solve for $b$ , we divide the product of $8$ and $240$ by $48$ . Simplifying the fraction, $\frac{240}{48} = 5$ , and multiplying by $8$ gives $b = 40$ .

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