Two water taps together can fill a tank in hours. The tap of larger diameter takes 5 hours less than the smaller one to fill the tank separately. Find the time in which each tap can fill the tank separately.
Answer: The smaller tap takes approximately hours and the larger tap takes approximately hours to fill the tank separately.
Step-by-step solution
Step 1: Define variables and rates
Let be the time taken by the smaller tap to fill the tank alone. Since the larger tap takes 5 hours less, its time will be . The rate at which a tap fills the tank is the reciprocal of the time it takes. So, the rate of the smaller tap is and the rate of the larger tap is .
Step 2: Formulate the combined rate equation
When both taps work together, their rates add up. The combined time to fill the tank is given as hours, which is hours. Therefore, the combined rate is . We set up the equation by summing the individual rates and equating it to the combined rate.
Step 3: Simplify the equation to a quadratic form
First, combine the fractions on the left side of the equation by finding a common denominator. Then, cross-multiply to eliminate the denominators. Expand and rearrange the terms to form a standard quadratic equation in the form .
Step 4: Solve the quadratic equation for
We use the quadratic formula to solve for . Substitute the coefficients , , and into the formula. Calculate the discriminant and then find the two possible values for .
Step 5: Determine the valid time for each tap
We have two possible values for . Since time cannot be negative, we must discard the solution that leads to a negative time for the larger tap. If hours, then hours, which is not physically possible. Thus, hours is the correct time for the smaller tap, and hours for the larger tap.
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