What is the probablity of landing two 6s on 2 die rolled 26 times?

Step 1: Determine the total number of outcomes for rolling two dice

When rolling two dice, each die has 6 possible outcomes (1, 2, 3, 4, 5, 6). To find the total number of possible outcomes when rolling two dice, we multiply the number of outcomes for each die. This gives us $6 \times 6 = 36$ possible combinations.

Step 2: Identify the number of favorable outcomes

We are looking for the probability of landing two 6s. There is only one way to achieve this specific outcome: the first die shows a 6, and the second die also shows a 6. So, the number of favorable outcomes is 1.

Step 3: Calculate the probability of rolling two 6s in a single roll

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In this case, the probability of rolling two 6s in a single roll is $1$ divided by $36$, which is $\frac{1}{36}$.

Step 4: Address the irrelevant information

The question asks for the probability of landing two 6s on two dice. The fact that the dice are rolled 26 times does not change the probability of this specific event occurring in any single roll. Each roll is an independent event, and its probability remains constant.

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