Write the set A = \{1, 4, 9, 16, 25, . . . \} in set-builder form.

Answer: A={x∣x=n2,n∈N}A = \{x \mid x = n^2, n \in \mathbb{N}\}

Step-by-step solution

Step 1: Identify the pattern

Observe the elements of the given set AA. We can see that each element is the square of a natural number. The first element is 121^2, the second is 222^2, the third is 323^2, and so on.

Step 2: Define the general term

Based on the observed pattern, we can represent any element xx in the set as the square of a natural number nn. Here, nn belongs to the set of natural numbers, denoted by N={1,2,3,...}\mathbb{N} = \{1, 2, 3, . . . \}.

Step 3: Write in set-builder form

Using the general term, we can write the set AA in set-builder form. This notation means 'the set of all xx such that xx is equal to n2n^2, where nn is a natural number'.

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