5x+3y=9(I)5x + 3y = 9 \quad \text{(I)} 2x−3y=12(II)2x - 3y = 12 \quad \text{(II)} (linear equations, system of equations, variables, coefficients)

Answer: The solution to the system of equations is x=3x=3 and y=−2y=-2.

Step-by-step solution

Step 1: Add the two equations

We have a system of two linear equations. Notice that the coefficients of yy are +3+3 and −3-3. Adding the two equations together will eliminate the yy variable, allowing us to solve for xx.

Step 2: Simplify and solve for x

After adding the equations, the 3y3y and −3y-3y terms cancel out, leaving us with 7x=217x = 21. Dividing both sides by 7 gives us the value of xx.

Step 3: Substitute x into one of the original equations

Now that we have the value of xx, we can substitute it into either of the original equations to find the value of yy. Let's use Equation (I): 5x+3y=95x + 3y = 9.

Step 4: Solve for y

Substitute x=3x=3 into the equation 5x+3y=95x + 3y = 9. This simplifies to 15+3y=915 + 3y = 9. Subtract 15 from both sides to get 3y=−63y = -6, and then divide by 3 to find y=−2y = -2.

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