If $6x + 08y = 43$ and $x = 5$ what is the value of y?

Step 1: Substitute the value of x

We are given the equation $6x + 8y = 43$ and the value $x = 5$. To find the value of $y$, we substitute $x=5$ into the equation. Note that $08y$ is the same as $8y$.

Step 2: Simplify the equation

After substituting $x=5$, we multiply $6$ by $5$ to simplify the term $6x$. This gives us $30$, resulting in the simplified equation $30 + 8y = 43$.

Step 3: Isolate the term with y

To isolate the term containing $y$, we need to move the constant term $30$ to the right side of the equation. We do this by subtracting $30$ from both sides.

Step 4: Calculate the difference

Now, we perform the subtraction on the right side of the equation: $43 - 30 = 13$. This simplifies the equation to $8y = 13$.

Step 5: Solve for y

Finally, to find the value of $y$, we divide both sides of the equation by $8$. This isolates $y$ and gives us its numerical value.

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