If $4x + 08y = 41$ and $x = 3$ what is the value of y?

Answer: The value of $y$ is $\frac{29}{8}$ .

Step-by-step solution

We are given the equation $4x + 8y = 41$ and the value of $x = 3$ . To find the value of $y$ , we substitute $x = 3$ into the equation.

Next, we multiply $4$ by $3$ to simplify the left side of the equation. This gives us $12 + 8y = 41$ .

To isolate the term with $y$ , we subtract $12$ from both sides of the equation. This moves the constant term to the right side.

Now, we perform the subtraction on the right side: $41 - 12 = 29$ . The equation becomes $8y = 29$ .

Finally, to solve for $y$ , we divide both sides of the equation by $8$ . This gives us the value of $y$ as a fraction.