Find the equation of the line, which makes intercepts -3 and 2 on the x- and y-axes respectively.

Answer: The equation of the line is 2x−3y+6=02x - 3y + 6 = 0.

Step-by-step solution

Step 1: Identify the intercepts

The problem states that the line makes an xx -intercept of −3-3 and a yy -intercept of 22. We denote the xx -intercept as aa and the yy -intercept as bb.

Step 2: Recall the intercept form of a line

The intercept form of the equation of a straight line is given by xa+yb=1\frac{x}{a} + \frac{y}{b} = 1, where aa is the xx -intercept and bb is the yy -intercept.

Step 3: Substitute the intercept values

Now, substitute the given values of the xx -intercept (a=−3a = -3) and the yy -intercept (b=2b = 2) into the intercept form equation.

Step 4: Simplify the equation

To simplify, find a common denominator for the fractions, which is 66. Multiply the entire equation by 66 to eliminate the denominators. Then, rearrange the terms to get the equation in the standard form Ax+By+C=0Ax + By + C = 0.

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