Let R\mathbf{R} be the set of real numbers. Define the real function f:R→R by f(x)=x+10f: \mathbf{R} \rightarrow \mathbf{R} \text { by } f(x)=x+10 and sketch the graph of this function.

Answer: The graph of the function f(x)=x+10f(x) = x+10 is a straight line passing through the points (−10,0)(-10, 0) and (0,10)(0, 10).

Step-by-step solution

Step 1: Understand the Function

The given function is a linear function of the form f(x)=mx+cf(x) = mx + c, where mm is the slope and cc is the yy -intercept. In this case, the slope m=1m=1 and the yy -intercept c=10c=10.

Step 2: Find Key Points

To sketch a linear function, we need at least two points. Let's choose a few simple xx values and calculate their corresponding f(x)f(x) values. For example, when x=0x=0, f(0)=0+10=10f(0) = 0+10 = 10. When x=−10x=-10, f(−10)=−10+10=0f(-10) = -10+10 = 0. When x=5x=5, f(5)=5+10=15f(5) = 5+10 = 15.

Step 3: Plot the Points and Draw the Line

Plot the calculated points (−10,0)(-10, 0), (0,10)(0, 10), and (5,15)(5, 15) on a coordinate plane. Since it's a linear function, connect these points with a straight line and extend it in both directions to represent the domain R\mathbf{R}.

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