**LONG ANSWER TYPE QUESTIONS** 1) If α\alpha and β\beta are different complex numbers with ∣β∣=1|\beta| = 1, then find ∣β−α1−αˉβ∣\left|\frac{\beta - \alpha}{1 - \bar{\alpha}\beta}\right| 2) If ∣a+ib∣=1|a + ib| = 1 then prove that (1+b+ia)(1+b−ia)=b+ia\frac{(1 + b + ia)}{(1 + b - ia)} = b + ia 3) If z=x+iyz = x + iy and the real part of zˉ+2zˉ−1\frac{\bar{z} + 2}{\bar{z} - 1} is 44, show that x2+y2−3x+2=0x^2 + y^2 - 3x + 2 = 0

Answer: Hence proved that x2+y2−3x+2=0x^2 + y^2 - 3x + 2 = 0.

Step-by-step solution

Step 1: Express zˉ\bar{z} in terms of xx and yy

Since z=x+iyz = x + iy, the complex conjugate zˉ\bar{z} is obtained by reversing the sign of the imaginary part, giving zˉ=x−iy\bar{z} = x - iy. We substitute this into the given expression zˉ+2zˉ−1\frac{\bar{z} + 2}{\bar{z} - 1}.

Step 2: Substitute and realize the denominator

Grouping the real and imaginary parts of both numerator and denominator gives (x+2)−iy(x−1)−iy\frac{(x + 2) - iy}{(x - 1) - iy}. To make the denominator a real number, we multiply both numerator and denominator by the conjugate of the denominator, which is (x−1)+iy(x - 1) + iy.

Step 3: Expand and simplify the fraction

Expanding the product in the numerator gives real part (x+2)(x−1)−(−y2)=x2+x−2+y2(x + 2)(x - 1) - (-y^2) = x^2 + x - 2 + y^2, and imaginary part y(x+2)−y(x−1)=3yy(x + 2) - y(x - 1) = 3y. The denominator simplifies to (x−1)2+y2(x - 1)^2 + y^2.

Step 4: Equate the real part to 44

The problem states that the real part of the expression is equal to 4. We set the real part equal to 4 and cross-multiply to form a polynomial equation.

Step 5: Cross-multiply and derive the required equation

Expanding the right side yields 4x2−8x+4+4y24x^2 - 8x + 4 + 4y^2. Subtracting x2+y2+x−2x^2 + y^2 + x - 2 from both sides gives 3x2+3y2−9x+6=03x^2 + 3y^2 - 9x + 6 = 0. Dividing the entire equation by 3 gives the desired result x2+y2−3x+2=0x^2 + y^2 - 3x + 2 = 0.

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