Application of Derivatives — Class 12 solved problems
26 problems from this chapter, each solved step by step.
- An empty inverted right circular conical vessel of base radius 12 cm and vertical height 18 cm is being filled with water at a constant rate of 12π cm³/s.At the
Total time elapsed is (55)/(3) s (or 18(1)/(3) s), and the water level rises instantly by ( [3]459 - 6) cm ≈ 1.71 cm.
- Find the local maximum and minimum values of f(x) = x * sqrt(4 - x²).
The local maximum value is 2 at x = √2 and the local minimum value is -2 at x = - √2.
- Find the maximum value of f(x) = 2x³ - 9x² + 12x + 5 on the interval [0, 3].
The maximum value of f(x) on the interval [0, 3] is 14.
- Find the equation of the tangent and normal to the curve y = x³ - 3x + 2 at x = 1.
The equation of the tangent is y = 0. The equation of the normal is x = 1.
- Find the local maxima and local minima of the function f(x) = sin(x) + cos(x) on the interval [0, 2*pi].
The function has a local maximum at x = (π)/(4) with value √2, and a local minimum at x = (5π)/(4) with value -√2.
- The rate of change of the area of a circle with respect to its radius r (in cm²/s), when r = 6 cm is:
12π cm²/cm
- (a) Find the intervals in R for which the function f(x) = x^4 - 2x² is increasing or decreasing. OR (b) Find: ∫ (2x + 1)/(√(18 - 4x - x²)) dx.
The function f(x) = x^4 - 2x² is increasing on the intervals (-1, 0) (1, ∞) and decreasing on the intervals (-∞, -1) (0, 1).
- Let f(x)=∫_0^x t(t²-9t+20) dt, 1 ≤ x ≤ 5. If the range of f is [α, β], then 4(α+β) equals:
157
- Let f: R → R be a polynomial function of degree four having extreme values at x = 4 and x = 5. If lim_x → 0 (f(x))/(x²) = 5, then f(2) is equal to:
10
- A particle moves in the plane with position vector r⃗(t) = (t², e^t). Find its velocity, acceleration, and the tangential and normal components of acceleration
At t=1: Velocity v(1) = (2, e), Acceleration a(1) = (2, e), Tangential component of acceleration a_T = √(4 + e²), Normal component of acceleration a_N = 0.
- Find the extrema of f(x,y,z) = xyz subject to the constraint x² + 2y² + 3z² = 6 using Lagrange multipliers.
The maximum value is (2√3)/(3) and the minimum value is -(2√3)/(3).
- If the set of all values of a, for which the equation 5x³ - 15x - a = 0 has three distinct real roots, is the interval (α, β), then β - 2α is equal to
30
- The sum of all local minimum values of the function f(x) = 1 - 2x, & x < -1 (1)/(3)(7 + 2|x|), & -1 ≤ x ≤ 2 (11)/(18)(x - 4)(x - 5), & x > 2 is
(157)/(72)
- A sphere of radius r is inscribed in a cone with base radius R and height h. Find the relationship between r, R, and h.
The relationship between r, R, and h is r = (Rh)/(R+h).
- Let x = -1 and x = 2 be the critical points of the function f(x) = x³ + ax² + b log_2|x| + 1, x 0. Let m and M respectively be the absolute minimum and the abso
23.68
- Let the function f(x) = (x)/(3) + (3)/(x) + 3, x 0 be strictly increasing in (-∞, _1) ( _2, ∞) and strictly decreasing in ( _1, _2) ( _4, _5). Then Σ_i=1^(5) _i
18
- Let f: [1, ∞) → [2, ∞) be a differentiable function. If ∫_1^x f(t) dt = 5x f(x) - x^5 - 9 for all x ≥ 1, then the value of f(3) is:
(274)/(27)
- Let f(x)=∫_0^x² (t²-8t+15)/(e^t) dt, x R. Then the numbers of local maximum and local minimum points of f, respectively, are:
The number of local maximum points is 2 and the number of local minimum points is 3.
- Let A(4, -2), B(1, 1) and C(9, -3) be the vertices of a triangle ABC. Then the maximum area of the parallelogram AFDE, formed with vertices D, E, and F on the s
The maximum area of the parallelogram AFDE is 3 square units.
- Find the maximum and minimum values of f(x) = sin(x) + cos(x) on the interval [0, π].
The maximum value of the function is √2 and the minimum value is -1 on the interval [0, π].
- Let (2, 3) be the largest open interval in which the function f(x) = 2 log_e (x - 2) - x² + a x + 1 is strictly increasing and (b, c) be the largest open interv
360
- If the function f(x)=2x³ - 9a x² + 12a² x + 1, where a>0, attains its local maximum and local minimum at p and q respectively, such that p² = q, then f(3) is eq
37
- A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm, the ice-cream melts at th
256π cm²
- EXTENSION: A sphere of radius r is inscribed in a cone with base radius R and height h. Find the relationship between r, R, and h. Additionally, generalize your
The relationship between r, R, and h is r = (Rh)/(R + √(R² + h²)). The generalization to n is not applicable as the problem describes a specific geometric confi
- Consider the region R = (x, y): x ≤ y ≤ 9 - (11)/(3) x², x ≥ 0. The area, of the largest rectangle of sides parallel to the coordinate axes and inscribed in R,
The area of the largest rectangle is (567)/(121).
- Find the equation of the tangent line to the curve y = x² - 2x + 7 which is parallel to the line 2x - y + 9 = 0.
The equation of the tangent line is y = 2x + 3.
More Class 12 chapters
- Relations and Functions39 solved
- Inverse Trigonometric Functions10 solved
- Matrices22 solved
- Determinants33 solved
- Continuity and Differentiability44 solved
- Integrals41 solved
- Application of Integrals28 solved
- Differential Equations29 solved
- Vector Algebra22 solved
- Three Dimensional Geometry37 solved
- Linear Programming5 solved
- Probability16 solved